IG
Algorithms (3)
L2 3L' U' 3L 2U' 3L' U 3L 2U L2
My choice
16 HTM · 10 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3L' U' 3L' 2D' 3L U 3L' 2D 3L2
16 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3R U' 3R 2D' 3R' U 3R 2D 3R2
16 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3L2 2D' 3L U' 3L' 2D 3L U 3L. Every algorithm above was run by our logic engine from that state and reaches "solved".