HX
Algorithms (3)
2L' 3D 2L' U2 2L 3D' 2L' U2 2L2
My choice
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
3B2 U' 2B' U 3B2 U' 2B U
12 HTM · 8 STM · 16 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
3F2 U' 2B' U 3F2 U' 2B U
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2B' U 3B2 U' 2B U 3B2. Every algorithm above was run by our logic engine from that state and reaches "solved".