HP
Algorithms (3)
3D 2L' U2 2L 3D2 2L' U2 2L 3D
My choice
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
y 3D2 2L' U 2L 3D2 2L' U' 2L y'
14 HTM · 8 STM · 18 QTM
3-gen
rotation
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2B' U' 2B 3D2 2B' U 2B 3D2
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<U,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y 2L' U 2L 3D2 2L' U' 2L 3D2 y'. Every algorithm above was run by our logic engine from that state and reaches "solved".