HM
Algorithms (3)
R' y 3D2 2L' U 2L 3D2 2L' U' 2L y' R
My choice
16 HTM · 10 STM · 20 QTM
rotation
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
4Dw' U' 3L' U 2R' U' 3L U 2R 4Dw
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
Lw 2U' 3L' U' 3L 2U2 3L' U 3L 2U' Lw'
18 HTM · 11 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 4Dw' 2R' U' 3L' U 2R U' 3L U 4Dw. Every algorithm above was run by our logic engine from that state and reaches "solved".