HA
Algorithms (3)
U 2R 3D' 2R' U' 2R 3D 2R'
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 7 solvers' sheets
3Lw 3F' 3Lw' 2B 3Lw 3F 3Lw' 2B'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
L 3F' L' 2B L 3F L' 2B'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2B 3Lw 3F' 3Lw' 2B' 3Lw 3F 3Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".