FI
Algorithms (3)
L' 2U' 3L' U' 3L 2U 3L' U 3L L
My choice
16 HTM · 10 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
Lw' 2U' 3L' U' 3L 2U 3L' U 3Lw
14 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
Lw' 2U' 3R U' 3R' 2U 3R U 3Lw
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw' U' 3L 2U' 3L' U 3L 2U Lw. Every algorithm above was run by our logic engine from that state and reaches "solved".