EA
Algorithms (3)
3L 2U' 3L' U' 3L 2U 3L' U
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 7 solvers' sheets
3F' L' 2B L 3F L' 2B' L
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
3F' Lw' 2B Lw 3F Lw' 2B' Lw
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L' 2B L 3F' L' 2B' L 3F. Every algorithm above was run by our logic engine from that state and reaches "solved".