DC
Algorithms (3)
3Rw' U2 2R U 3L' U' 2R' U 3L U 3Rw
My choice
15 HTM · 11 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Lw2 3Dw' 2R2 3Dw 3F2 3Dw' 2R2 3Dw 3F2 3Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,F,D,L>
One hand: needs L, B, S or E
Cubemuch
Rw2 3Uw' 2R2 3Uw 3F2 3Uw' 2R2 3Uw 3F2 Rw2
14 HTM · 10 STM · 24 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw2 3F2 3Dw' 2R2 3Dw 3F2 3Dw' 2R2 3Dw 3Lw2. Every algorithm above was run by our logic engine from that state and reaches "solved".