CU
Algorithms (3)
U 3L' 2U2 3L U' 3L' 2U2 3L
My choice
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 15 solvers' sheets
U 3L 2D2 3L' U' 3L 2D2 3L'
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
D2 3L2 D' 2R2 D 3L2 D' 2R2 D'
13 HTM · 9 STM · 22 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3L 2D2 3L' U 3L 2D2 3L' U'. Every algorithm above was run by our logic engine from that state and reaches "solved".