CH
Algorithms (3)
2R 3D' 2R' U' 2R 3D 2R' U
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 16 solvers' sheets
Lw U 3L' 2U 3L U' 3L' 2U' 3L Lw'
16 HTM · 10 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R 3D' 2R' Uw' 2R 3D 2R' Uw
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Lw 3L' 2U 3L U 3L' 2U' 3L U' Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".