CF
Algorithms (3)
2R' 3D 2R U' 2R' 3D' 2R U
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 16 solvers' sheets
Lw' U 3L' 2U 3L U' 3L' 2U' 3Lw
14 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2F' 3Lw' 3F' 3Lw 2F 3Lw' 3F 3Lw
12 HTM · 8 STM · 12 QTM
2-gen
rotationless
<F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw' 2U 3L U 3L' 2U' 3L U' Lw. Every algorithm above was run by our logic engine from that state and reaches "solved".