AF
Algorithms (3)
2R' 3D 2R U 2R' 3D' 2R U'
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 7 solvers' sheets
2R' 3D 2R Uw 2R' 3D' 2R Uw'
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
U 3Lw' 3F' 3Lw 2F' 3Lw' 3F 3Lw 2F U'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Uw 2R' 3D 2R Uw' 2R' 3D' 2R. Every algorithm above was run by our logic engine from that state and reaches "solved".