AD
Algorithms (3)
3Lw2 3F2 U 2F2 U' 3F2 U 2F2 U' 3Lw2
My choice
14 HTM · 10 STM · 24 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
Cubemuch
3Rw2 U' 2F2 U 3F2 U' 2F2 U 3F2 3Rw2
14 HTM · 10 STM · 24 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
Lw2 Dw' 2B2 Dw 3F2 Dw' 2B2 Dw 3F2 Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<F,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Rw2 3F2 U' 2F2 U 3F2 U' 2F2 U 3Rw2. Every algorithm above was run by our logic engine from that state and reaches "solved".