UA
Algorithms (3)
3L' U2 3L U2
My choice
6 HTM · 4 STM · 8 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 15 solvers' sheets
3R U2 3R' U2
6 HTM · 4 STM · 8 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
3R' D2 3R' D2 3R2
8 HTM · 5 STM · 12 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U2 3R U2 3R'. Every algorithm above was run by our logic engine from that state and reaches "solved".