KJ
Algorithms (3)
U' R U 3L' U' R' U 3L
My choice
10 HTM · 8 STM · 10 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 14 solvers' sheets
U' R U 3R U' R' U 3R'
10 HTM · 8 STM · 10 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
3R2 D' R' D 3R D' R D 3R
12 HTM · 9 STM · 14 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3R U' R U 3R' U' R' U. Every algorithm above was run by our logic engine from that state and reaches "solved".