KA
Algorithms (3)
U 3L U 3L U2 3L' U 3L' U'
My choice
13 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 8 solvers' sheets
U' 3L U' 3L U2 3L' U' 3L' U
13 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
D' U2 3L D 3L' U2 3L D' 3L' D
14 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 3L U 3L U2 3L' U 3L' U. Every algorithm above was run by our logic engine from that state and reaches "solved".