EPLL parity 4
EPLL parity
With the corners solved, find the swapped or cycled dedges, as for EPLL.
Your status
Algorithms (5)
B2 U' L' R B2 L R' U' B2
My choice
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
B2 U' R L' B2 R' L U' B2
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
(U) first, then:
R2 U' F B' R2 F' B U' R2
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
(U') first, then:
L2 U' B F' L2 B' F U' L2
9 HTM · 9 STM · 12 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
(U2) first, then:
F2 U' L R' F2 L' R U' F2
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: B2 U L' R B2 L R' U B2. Every algorithm above was run by our logic engine from that state and reaches "pll-solved", keeping first-layers and oll-solved.