EPLL parity 1
EPLL parity
With the corners solved, find the swapped or cycled dedges, as for EPLL.
Your status
Algorithms (5)
(U') first, then:
B2 U L' R B2 L R' U B2
My choice
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
R2 U F B' R2 F' B U R2
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
(U2) first, then:
L2 U B F' L2 B' F U L2
9 HTM · 9 STM · 12 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
(U) first, then:
F2 U R' L F2 R L' U F2
9 HTM · 9 STM · 12 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
(U') first, then:
L2 U L U L' U' L' U' L' U L'
11 HTM · 11 STM · 12 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
Do U' first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R2 U' B' F R2 B F' U' R2. Every algorithm above was run by our logic engine from that state and reaches "pll-solved", keeping first-layers and oll-solved.