Three flipped 19
OLL parity (3 flips)
Count the flipped dedges (three here), then read the corner shape.
Your status
Algorithms (3)
(U) first, then:
Rw F U2 F' Rw U2 Rw U2 Rw U' L' U2 L F 3Lw' U'
R U' x' U F Rw
My choice
21 HTM · 21 STM · 25 QTM
rotation
<U,R,F,L>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
U' Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2
Rw' U2 Rw' U' 3Rw U R' U R U' R' U R U2 3Rw'
30 HTM · 30 STM · 39 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2F 3F U' 2F' 3F' R 2R U2 2R' R' U2 R 2R B2 R 2R
R 2R U2 2R' R' U2 R 2R U2 B2 R 2R R 2R B2 2F
3F U 2F' 3F'
53 HTM · 36 STM · 61 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Rw U2 R' U' R U R' U' R U' 3Rw' U Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' U. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.