Three flipped 15
OLL parity (3 flips)
Count the flipped dedges (three here), then read the corner shape.
Your status
Algorithms (4)
U2 B' R' U R U Rw U2 x Rw U2 Rw U2 Rw' U2 Lw
U2 Rw' U2 Rw U2 Rw' U2 Rw' U' R' U' R B
My choice
28 HTM · 28 STM · 37 QTM
rotation
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
U Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2
Rw' U2 Rw' 3Rw' U2 R U R' U' R U R' U 3Rw
29 HTM · 29 STM · 38 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2F' 3F' U 2F 3F R 2R U2 2R' R' U2 R 2R B2 R 2R
R 2R U2 2R' R' U2 R 2R U2 B2 R 2R R 2R B2 2F'
3F' U' 2F 3F
53 HTM · 36 STM · 61 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
y2 2F 3F U 2F' 3F' R 2R R 2R B2 2R' R' U2 2R' R'
U2 B2 2R' R' B2 R 2R B2 2R' R' B2 R 2R R 2R B2
2F 3F U 2F' 3F'
53 HTM · 36 STM · 61 QTM
rotation
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Rw' U' R U' R' U R U' R' U2 3Rw Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' U'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.