Three flipped 11
OLL parity (3 flips)
Count the flipped dedges (three here), then read the corner shape.
Your status
Algorithms (4)
(U) first, then:
B' R' Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw
U2 Rw' U2 Rw' R B
My choice
21 HTM · 21 STM · 29 QTM
rotation
<U,R,L,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
U B' R' Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2
Rw U2 Rw' U2 Rw' R B
22 HTM · 22 STM · 30 QTM
rotation
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
y F R R 2R U2 2R' R' U2 R 2R B2 R 2R R 2R
U2 2R' R' U2 R 2R U2 B2 R 2R R 2R B2 R' F'
39 HTM · 30 STM · 47 QTM
rotation
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
(U) first, then:
B' R' R 2R R 2R B2 U2 L 2L U2 2R' R' U2 R 2R
U2 F2 R 2R F2 2L' L' B2 R 2R R 2R R B
39 HTM · 30 STM · 47 QTM
rotationless
<U,R,F,L,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: B' R' Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' R B U'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.