Three flipped 1
OLL parity (3 flips)
Count the flipped dedges (three here), then read the corner shape.
Your status
Algorithms (5)
Rw U' R U2 R' U2 R' U' Rw U2 Rw R U2 Rw U' R'
U2 R' U2 R U' Rw
My choice
22 HTM · 22 STM · 28 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
Rw U' R U2 R' U2 R' U' Rw U2 Rw R U2 Rw U' Rw'
U2 R' U2 Rw U' Rw
22 HTM · 22 STM · 28 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
Rw U' Rw U2 R' U2 Rw' U' Rw U2 Rw R U2 Rw U' Rw'
U2 R' U2 Rw U' Rw
22 HTM · 22 STM · 28 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
(U) first, then:
Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw'
U2 Rw' U F U R U2 R' U' R U R' F'
28 HTM · 28 STM · 37 QTM
rotation
<U,R,F,L>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
(U) first, then:
U F R U R' U' F' U' F U R U' R' F' Rw U2
x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
31 HTM · 31 STM · 39 QTM
rotation
<U,R,F,L>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Rw' U Rw' U2 R U2 Rw U Rw' U2 R' Rw' U2 Rw' U R U2 R U2 R' U Rw'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.