U (R)
OLL parity (1 flip)
2 Corners
Count the flipped dedges (one here), then read the corner shape as for OLL.
Your status
Algorithms (3)
(U) first, then:
U' B L Rw2 B2 Rw' U2 Rw' U2 x' U2 Rw' U2 Rw U2 Rw'
U2 Rw2 U2 x U2 L' B'
My choice
21 HTM · 21 STM · 32 QTM
rotation
<U,R,L,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2 Rw U2 Rw'
U2 Rw' U' R U R' U R U2 R'
25 HTM · 25 STM · 34 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
B L R 2R R 2R B2 2R' R' U2 2R' R' U2 B2 2R' R'
B2 R 2R B2 2R' R' B2 R 2R R 2R B2 U2 L' B'
40 HTM · 31 STM · 49 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R U2 R' U' R U' R' U Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.