Sune (BR)
OLL parity (1 flip)
1 Corner
Count the flipped dedges (one here), then read the corner shape as for OLL.
Your status
Algorithms (5)
(U2) first, then:
Rw U2 Rw U2 Rw U R Rw U2 R2 U Rw U Rw2 R U
Rw U' Rw
My choice
19 HTM · 19 STM · 24 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Do U2 first (AUF) on the case as drawn. · Cubemuch
L F' L' F Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw'
U2 Rw U2 Rw' U2 Rw' L' U L
24 HTM · 24 STM · 32 QTM
rotation
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
(U2) first, then:
U2 L F' L' F Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2
Rw' U2 Rw U2 Rw' U2 Rw' L' U L
25 HTM · 25 STM · 34 QTM
rotation
<U,R,F,L>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
(U2) first, then:
R' U2 R U R' U R U2 Rw U2 x Rw U2 Rw U2 Rw'
U2 Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
25 HTM · 25 STM · 35 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Do U2 first (AUF) on the case as drawn. · Cubemuch
y R' 2L 3L R 2R R 2R B2 2R' R' U2 2R' R' U2 B2
2R' R' B2 R 2R B2 2R' R' B2 R 2R R 2R B2 R U
R' U R 2L' 3L'
49 HTM · 36 STM · 57 QTM
rotation
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L' U' L Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' F' L F L'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.