L (FL)
OLL parity (1 flip)
2 Corners
Count the flipped dedges (one here), then read the corner shape as for OLL.
Your status
Algorithms (5)
L U L' Rw2 B2 U2 Lw U2 Rw' U2 Rw U2 F2 Rw F2 Lw'
B2 Rw2 L U' L'
My choice
21 HTM · 21 STM · 31 QTM
rotationless
<U,R,F,L,B>
One hand: needs L, B, S or E
Cubemuch
L U L' Rw U2 x Rw U2 Rw U2 Rw' U2 Lw U2 Rw' U2
Rw U2 Rw' U2 Rw' L U' L'
23 HTM · 23 STM · 31 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
(U) first, then:
R U R' U R U2 R' Rw U2 x Rw U2 Rw U2 Rw' U2
Lw U2 Rw' U2 Rw U2 Rw' U2 Rw'
24 HTM · 24 STM · 33 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
(U) first, then:
y' L U L' R 2R R 2R B2 U2 L 2L U2 2R' R' U2
R 2R U2 F2 R 2R F2 2L' L' B2 R 2R R 2R L U'
L'
41 HTM · 32 STM · 49 QTM
rotation
<U,R,F,L,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
(U) first, then:
L' B' L R 2R R 2R B2 2R' R' U2 2R' R' U2 B2 2R'
R' B2 R 2R B2 2R' R' B2 R 2R R 2R B2 U2 L' B
L
42 HTM · 33 STM · 51 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Do U first (AUF) on the case as drawn. · Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L U L' Rw U2 Rw U2 Rw' U2 Rw U2 Lw' U2 Rw U2 Rw' U2 Rw' x' U2 Rw' L U' L'. Every algorithm above was run by our logic engine from that state and reaches "oll-solved", keeping first-layers.