WX
Algorithms (3)
U2 2L2 U' 2R2 U 2L2 U' 2R2 U'
My choice
13 HTM · 9 STM · 22 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
Uw2 2L2 Uw' 2R2 Uw 2L2 Uw' 2R2 Uw'
13 HTM · 9 STM · 22 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
U Dw 2F2 Dw' 2R2 Dw 2F2 Dw' 2R2 U'
14 HTM · 10 STM · 22 QTM
rotationless
<U,R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Uw 2R2 Uw 2L2 Uw' 2R2 Uw 2L2 Uw2. Every algorithm above was run by our logic engine from that state and reaches "solved".