VX
Algorithms (3)
Rw' D F' 2L' F 2R2 F' 2L F 2R2 D' Rw
My choice
16 HTM · 12 STM · 20 QTM
rotationless
<R,F,D,L>
One hand: needs L, B, S or E
Cubemuch
Fw' U2 2L2 Uw' 2R' Uw 2L2 Uw' 2R Uw U2 Fw
16 HTM · 12 STM · 22 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
U Rw F 2R2 F 2L' F' 2R2 F 2L F2 Rw' U'
17 HTM · 13 STM · 22 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Fw' U2 Uw' 2R' Uw 2L2 Uw' 2R Uw 2L2 U2 Fw. Every algorithm above was run by our logic engine from that state and reaches "solved".