TQ
Algorithms (3)
B' 2R' U' 2L U 2R U' 2L' U B
My choice
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
B 2U' 2B 2U B' 2U' 2B' 2U
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
B' 2R' Uw' 2L Uw 2R Uw' 2L' Uw B
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U' 2B 2U B 2U' 2B' 2U B'. Every algorithm above was run by our logic engine from that state and reaches "solved".