TL
Algorithms (3)
2D2 2L' U2 2L 2D2 2L' U2 2L
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 7 solvers' sheets
F U' 2L' U 2R' U' 2L U 2R F'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
F 2R B' 2L2 B 2R' B' 2L2 B F'
14 HTM · 10 STM · 18 QTM
rotationless
<R,F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F 2R' U' 2L' U 2R U' 2L U F'. Every algorithm above was run by our logic engine from that state and reaches "solved".