QX
Algorithms (3)
U2 2L2 U' 2R' U 2L2 U' 2R U'
My choice
13 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
U 2R B 2L B' 2R' B 2L' B' U'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
2L B 2L' 2B2 2L B' 2L' 2B2
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U B 2L B' 2R B 2L' B' 2R' U'. Every algorithm above was run by our logic engine from that state and reaches "solved".