PO
Algorithms (3)
2D 2R 2D' R 2D 2R' 2D' R'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
2B U 2F' U' 2B' U 2F U'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
2B Dw 2R' Dw' 2B' Dw 2R Dw'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 2F' U' 2B U 2F U' 2B'. Every algorithm above was run by our logic engine from that state and reaches "solved".