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Algorithms (3)
2D 2R 2D' R' 2D 2R' 2D' R
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
R 2F 2R2 2F' R' 2F 2R2 2F'
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
Cubemuch
R' U 2F' U' 2B U 2F U' 2B' R
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2F 2R2 2F' R 2F 2R2 2F' R'. Every algorithm above was run by our logic engine from that state and reaches "solved".