PK
Algorithms (3)
F 2D' 2L' U2 2L 2D 2L' U2 2L F'
My choice
16 HTM · 10 STM · 18 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
Rw Uw U 2L' U 2R' U' 2L U 2R U2 Uw' Rw'
17 HTM · 13 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
R' 2B' Rw 2F Rw' 2B Rw 2F' 2R'
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Rw Uw U2 2R' U' 2L' U 2R U' 2L U' Uw' Rw'. Every algorithm above was run by our logic engine from that state and reaches "solved".