NM
Algorithms (3)
2U 2R' 2U' R 2U 2R 2U' R'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
U2 2F' U 2B U' 2F U 2B' U
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
R' 2F 2R2 2F' R 2F 2R2 2F'
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2B U' 2F' U 2B' U' 2F U2. Every algorithm above was run by our logic engine from that state and reaches "solved".