NG
Algorithms (3)
E' U' 2L U 2R U' 2L' U 2R' E
My choice
16 HTM · 10 STM · 16 QTM
rotationless
<U,R,L,E>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
L' 2U' 2L U2 2L' 2U2 2L U2 2L' 2U' L
18 HTM · 11 STM · 22 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U2 2F U 2B U' 2F' U 2B' U
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L' 2U 2L U2 2L' 2U2 2L U2 2L' 2U L. Every algorithm above was run by our logic engine from that state and reaches "solved".