LJ
Algorithms (3)
2L 2B2 2L' F2 2L 2B2 2L' F2
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
F 2U 2B 2U' F2 2U 2B' 2U' F
15 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
F' 2D 2B' 2D' F2 2D 2B 2D' F'
15 HTM · 9 STM · 16 QTM
3-gen
rotationless
<F,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' 2U 2B 2U' F2 2U 2B' 2U' F'. Every algorithm above was run by our logic engine from that state and reaches "solved".