KJ
Algorithms (3)
F' U' 2L' U 2R U' 2L U 2R' F
My choice
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
Cubemuch
Uw2 2L Uw' 2R Uw 2L' Uw' 2R' Uw'
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2D 2B' 2D' F 2D 2B 2D' F'
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<F,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Uw 2R Uw 2L Uw' 2R' Uw 2L' Uw2. Every algorithm above was run by our logic engine from that state and reaches "solved".