KH
Algorithms (3)
S 2D' 2R U2 2R' 2D 2R U2 2R' S'
My choice
18 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,S>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
F 2L' U2 2L 2D 2L' U2 2L 2D' F'
16 HTM · 10 STM · 18 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
L' 2D' 2F U2 2F' 2D 2F U2 2F' L
16 HTM · 10 STM · 18 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F 2D 2L' U2 2L 2D' 2L' U2 2L F'. Every algorithm above was run by our logic engine from that state and reaches "solved".