KF
Algorithms (3)
Uw U 2L U' 2R U 2L' U' 2R' Uw'
My choice
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
F' 2U2 2L U2 2L' 2U' 2L U2 2L' 2U' F
18 HTM · 11 STM · 22 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
F' 2R' B' 2U' B 2R B' 2U B F
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' 2U 2L U2 2L' 2U 2L U2 2L' 2U2 F. Every algorithm above was run by our logic engine from that state and reaches "solved".