JF
Algorithms (3)
U' 2R U 2R' 2U' 2R U' 2R' Uw
My choice
14 HTM · 9 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 5 solvers' sheets
2U2 2L U2 2L' 2U' 2L U2 2L' 2U'
16 HTM · 9 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R' B' 2U' B 2R B' 2U B
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U 2L U2 2L' 2U 2L U2 2L' 2U2. Every algorithm above was run by our logic engine from that state and reaches "solved".