IE
Algorithms (3)
2L' U' 2L 2U' 2L' U 2L 2U
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 8 solvers' sheets
Lw 2F Lw' 2B Lw 2F' Lw' 2B'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
2U R' 2B R 2U' R' 2B' R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2B Lw 2F Lw' 2B' Lw 2F' Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".