HU
Algorithms (3)
2D' U' 2L2 U 2R' U' 2L2 U 2R 2D
My choice
16 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
y' x U 2L U 2R U' 2L' U 2R' U2 x' y
13 HTM · 9 STM · 14 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
L 2B L 2F L' 2B' L 2F' L2
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y' x U2 2R U' 2L U 2R' U' 2L' U' x' y. Every algorithm above was run by our logic engine from that state and reaches "solved".