HP
Algorithms (3)
2D 2L' U2 2L 2D2 2L' U2 2L 2D
My choice
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
L U 2F' U' 2B' U 2F U' 2B L'
14 HTM · 10 STM · 14 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Cubemuch
Lw U 2F' U' 2B' U 2F U' 2B Lw'
14 HTM · 10 STM · 14 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L 2B' U 2F' U' 2B U 2F U' L'. Every algorithm above was run by our logic engine from that state and reaches "solved".