HE
Algorithms (3)
2D' 2R 2D L' 2D' 2R' 2D L
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
2D' 2R 2D Lw' 2D' 2R' 2D Lw
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
Rw B 2U B' 2D' B 2U' B' 2D Rw'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Lw' 2D' 2R 2D Lw 2D' 2R' 2D. Every algorithm above was run by our logic engine from that state and reaches "solved".