HC
Algorithms (3)
U' 2R 2D' 2R' U 2R 2D 2R'
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 21 solvers' sheets
U 2L 2D 2L' U 2L 2D' 2L' U2
15 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
Cubemuch
Uw' 2R 2D' 2R' Uw 2R 2D 2R'
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U2 2L 2D 2L' U' 2L 2D' 2L' U'. Every algorithm above was run by our logic engine from that state and reaches "solved".