FV
Algorithms (3)
U' 2R 2U' 2R U 2R' 2U 2R U' 2R2 U
My choice
18 HTM · 11 STM · 20 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 4 solvers' sheets
L' 2R2 Uw' 2L' Uw 2R2 Uw' 2L Uw L
14 HTM · 10 STM · 18 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R2 2B L' 2B' 2R2 2B L 2B'
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L' Uw' 2L' Uw 2R2 Uw' 2L Uw 2R2 L. Every algorithm above was run by our logic engine from that state and reaches "solved".