FN
Algorithms (3)
2U 2L U2 2L' 2U2 2L U2 2L' 2U
My choice
16 HTM · 9 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
2U' B 2R' B' 2U2 B 2R B' 2U'
14 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
R 2B U 2F U' 2B' U 2F' U' R'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U B 2R' B' 2U2 B 2R B' 2U. Every algorithm above was run by our logic engine from that state and reaches "solved".