FH
Algorithms (3)
2U' 2R' 2U L2 2U' 2R 2U L2
My choice
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2U' 2R' 2U Lw2 2U' 2R 2U Lw2
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
L2 2D' 2R 2D L2 2D' 2R' 2D
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Lw2 2U' 2R' 2U Lw2 2U' 2R 2U. Every algorithm above was run by our logic engine from that state and reaches "solved".