FE
Algorithms (3)
2U B' 2U' 2B 2U B 2U' 2B'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
2U' 2R' 2U' R 2U 2R 2U' R' 2U2
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
2B' U 2F U' 2B U 2F' U'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U2 R 2U 2R' 2U' R' 2U 2R 2U. Every algorithm above was run by our logic engine from that state and reaches "solved".