FA
Algorithms (3)
U 2R' 2U' 2R U' 2R' 2U 2R
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 15 solvers' sheets
U 2F' L' 2B L 2F L' 2B' L U'
14 HTM · 10 STM · 14 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Cubemuch
U 2F' Lw' 2B Lw 2F Lw' 2B' Lw U'
14 HTM · 10 STM · 14 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U L' 2B L 2F' L' 2B' L 2F U'. Every algorithm above was run by our logic engine from that state and reaches "solved".